Base | Representation |
---|---|
bin | 1011111010100001110101… |
… | …0101011100000100001100 |
3 | 1201101100202110010011010100 |
4 | 2332220131111130010030 |
5 | 3204113042424141134 |
6 | 43510042232011100 |
7 | 2521311512144352 |
oct | 276503525340414 |
9 | 51340673104110 |
10 | 13100142412044 |
11 | 41a08149650a6 |
12 | 1576a8b230a90 |
13 | 740451b3b02c |
14 | 33409bd577d2 |
15 | 17ab71152999 |
hex | bea1d55c10c |
13100142412044 has 36 divisors (see below), whose sum is σ = 33204478469344. Its totient is φ = 4354815729312.
The previous prime is 13100142411989. The next prime is 13100142412061. The reversal of 13100142412044 is 44021424100131.
13100142412044 is a `hidden beast` number, since 1 + 3 + 100 + 142 + 412 + 0 + 4 + 4 = 666.
It is a tau number, because it is divible by the number of its divisors (36).
It is a super-2 number, since 2×131001424120442 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13100142411999 and 13100142412017.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 495753607 + ... + 495780030.
Almost surely, 213100142412044 is an apocalyptic number.
It is an amenable number.
13100142412044 is an abundant number, since it is smaller than the sum of its proper divisors (20104336057300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100142412044 is a wasteful number, since it uses less digits than its factorization.
13100142412044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 991534014 (or 991534009 counting only the distinct ones).
The product of its (nonzero) digits is 3072, while the sum is 27.
Adding to 13100142412044 its reverse (44021424100131), we get a palindrome (57121566512175).
The spelling of 13100142412044 in words is "thirteen trillion, one hundred billion, one hundred forty-two million, four hundred twelve thousand, forty-four".
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