1310014344040 has 32 divisors (see below), whose sum is σ = 2956278691080. Its totient is φ = 522450819072.

The previous prime is 1310014344031. The next prime is 1310014344043. The reversal of 1310014344040 is 404434100131.

It can be written as a sum of positive squares in 4 ways, for example, as 700425043396 + 609589300644 = 836914^2 + 780762^2 .

It is a super-2 number, since 2×1310014344040² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310014343996 and 1310014344014.

It is not an unprimeable number, because it can be changed into a prime (1310014344043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 48577557 + ... + 48604516.

Almost surely, 2^{1310014344040} is an apocalyptic number.

1310014344040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1310014344040 is an abundant number, since it is smaller than the sum of its proper divisors (1646264347040).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310014344040 is a wasteful number, since it uses less digits than its factorization.

1310014344040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97182421 (or 97182417 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1310014344040 its reverse (404434100131), we get a palindrome (1714448444171).

The spelling of 1310014344040 in words is "one trillion, three hundred ten billion, fourteen million, three hundred forty-four thousand, forty".