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131001557 is a prime number
BaseRepresentation
bin1111100111011…
…10110011010101
3100010111120100112
413303232303111
5232014022212
620555452405
73150331511
oct763566325
9303446315
10131001557
1167a46455
1237a57105
13211a961b
1413581141
15b77a422
hex7ceecd5

131001557 has 2 divisors, whose sum is σ = 131001558. Its totient is φ = 131001556.

The previous prime is 131001553. The next prime is 131001569. The reversal of 131001557 is 755100131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 120978001 + 10023556 = 10999^2 + 3166^2 .

It is an emirp because it is prime and its reverse (755100131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131001557 - 22 = 131001553 is a prime.

It is a super-2 number, since 2×1310015572 = 34322815872848498, which contains 22 as substring.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131001553) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65500778 + 65500779.

It is an arithmetic number, because the mean of its divisors is an integer number (65500779).

Almost surely, 2131001557 is an apocalyptic number.

It is an amenable number.

131001557 is a deficient number, since it is larger than the sum of its proper divisors (1).

131001557 is an equidigital number, since it uses as much as digits as its factorization.

131001557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 525, while the sum is 23.

The square root of 131001557 is about 11445.5911599183. The cubic root of 131001557 is about 507.8773199220.

Adding to 131001557 its reverse (755100131), we get a palindrome (886101688).

The spelling of 131001557 in words is "one hundred thirty-one million, one thousand, five hundred fifty-seven".