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1310020000301 = 1474788832983
BaseRepresentation
bin10011000100000011010…
…001101101101000101101
311122020101112202012121102
4103010003101231220231
5132430410110002201
62441452003012445
7163434342163265
oct23040321555055
94566345665542
101310020000301
11465638157781
12191a8306a125
13966c3c981bc
14475962367a5
152412393426b
hex1310346da2d

1310020000301 has 4 divisors (see below), whose sum is σ = 1310108848032. Its totient is φ = 1309931152572.

The previous prime is 1310020000217. The next prime is 1310020000313. The reversal of 1310020000301 is 1030000200131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1310020000301 - 234 = 1292840131117 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310020003301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44401745 + ... + 44431238.

It is an arithmetic number, because the mean of its divisors is an integer number (327527212008).

Almost surely, 21310020000301 is an apocalyptic number.

It is an amenable number.

1310020000301 is a deficient number, since it is larger than the sum of its proper divisors (88847731).

1310020000301 is an equidigital number, since it uses as much as digits as its factorization.

1310020000301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 88847730.

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 1310020000301 its reverse (1030000200131), we get a palindrome (2340020200432).

The spelling of 1310020000301 in words is "one trillion, three hundred ten billion, twenty million, three hundred one", and thus it is an aban number.

Divisors: 1 14747 88832983 1310020000301