Base | Representation |
---|---|
bin | 10011000100000011010… |
… | …001110100111000110011 |
3 | 11122020101112210201100111 |
4 | 103010003101310320303 |
5 | 132430410111430003 |
6 | 2441452003402151 |
7 | 163434342346006 |
oct | 23040321647063 |
9 | 4566345721314 |
10 | 1310020030003 |
11 | 465638178023 |
12 | 191a83083357 |
13 | 966c3ca8889 |
14 | 4759624353d |
15 | 2412393ce6d |
hex | 13103474e33 |
1310020030003 has 2 divisors, whose sum is σ = 1310020030004. Its totient is φ = 1310020030002.
The previous prime is 1310020030001. The next prime is 1310020030049. The reversal of 1310020030003 is 3000300200131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1310020030003 - 21 = 1310020030001 is a prime.
It is a super-2 number, since 2×13100200300032 (a number of 25 digits) contains 22 as substring.
Together with 1310020030001, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1310020030001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655010015001 + 655010015002.
It is an arithmetic number, because the mean of its divisors is an integer number (655010015002).
Almost surely, 21310020030003 is an apocalyptic number.
1310020030003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310020030003 is an equidigital number, since it uses as much as digits as its factorization.
1310020030003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 13.
Adding to 1310020030003 its reverse (3000300200131), we get a palindrome (4310320230134).
The spelling of 1310020030003 in words is "one trillion, three hundred ten billion, twenty million, thirty thousand, three".
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