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1310020221210 = 23543667340707
BaseRepresentation
bin10011000100000011010…
…010100011100100011010
311122020101120011102122020
4103010003102203210122
5132430410134034320
62441452011435310
7163434344103321
oct23040322434432
94566346142566
101310020221210
11465638298748
12191a83155b36
13966c404490c
14475962930b8
1524123979940
hex131034a391a

1310020221210 has 16 divisors (see below), whose sum is σ = 3144048530976. Its totient is φ = 349338725648.

The previous prime is 1310020221199. The next prime is 1310020221241. The reversal of 1310020221210 is 121220200131.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 1310020221210.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 21833670324 + ... + 21833670383.

It is an arithmetic number, because the mean of its divisors is an integer number (196503033186).

Almost surely, 21310020221210 is an apocalyptic number.

1310020221210 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1310020221210 is an abundant number, since it is smaller than the sum of its proper divisors (1834028309766).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310020221210 is a wasteful number, since it uses less digits than its factorization.

1310020221210 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43667340717.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 1310020221210 its reverse (121220200131), we get a palindrome (1431240421341).

The spelling of 1310020221210 in words is "one trillion, three hundred ten billion, twenty million, two hundred twenty-one thousand, two hundred ten".

Divisors: 1 2 3 5 6 10 15 30 43667340707 87334681414 131002022121 218336703535 262004044242 436673407070 655010110605 1310020221210