Base | Representation |
---|---|
bin | 10011000100000011011… |
… | …101101001111111111011 |
3 | 11122020101202122021022002 |
4 | 103010003131221333323 |
5 | 132430411410144011 |
6 | 2441452154051215 |
7 | 163434410613131 |
oct | 23040335517773 |
9 | 4566352567262 |
10 | 1310023131131 |
11 | 4656399a5a40 |
12 | 191a84119b0b |
13 | 966c4823270 |
14 | 4759680d751 |
15 | 24123d51c3b |
hex | 13103769ffb |
1310023131131 has 32 divisors (see below), whose sum is σ = 1635191712000. Its totient is φ = 1031727646080.
The previous prime is 1310023131083. The next prime is 1310023131163. The reversal of 1310023131131 is 1311313200131.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1310023131131 is a prime.
It is a super-2 number, since 2×13100231311312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1310023131931) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1962356 + ... + 2543793.
It is an arithmetic number, because the mean of its divisors is an integer number (51099741000).
Almost surely, 21310023131131 is an apocalyptic number.
1310023131131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1310023131131 is a deficient number, since it is larger than the sum of its proper divisors (325168580869).
1310023131131 is a wasteful number, since it uses less digits than its factorization.
1310023131131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4506299.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 1310023131131 its reverse (1311313200131), we get a palindrome (2621336331262).
The spelling of 1310023131131 in words is "one trillion, three hundred ten billion, twenty-three million, one hundred thirty-one thousand, one hundred thirty-one".
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