Base | Representation |
---|---|
bin | 1011111010100010011011… |
… | …1111100010101111110011 |
3 | 1201101101011202000020201211 |
4 | 2332220212333202233303 |
5 | 3204113410414210103 |
6 | 43510110300540551 |
7 | 2521315520330041 |
oct | 276504677425763 |
9 | 51341152006654 |
10 | 13100304444403 |
11 | 41a0898375440 |
12 | 1576b15551757 |
13 | 740479590877 |
14 | 3340b5695391 |
15 | 17ab804ac36d |
hex | bea26fe2bf3 |
13100304444403 has 8 divisors (see below), whose sum is σ = 14292140166576. Its totient is φ = 11908618548000.
The previous prime is 13100304444391. The next prime is 13100304444439. The reversal of 13100304444403 is 30444440300131.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13100304444403 - 25 = 13100304444371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13100304444103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37273576 + ... + 37623397.
It is an arithmetic number, because the mean of its divisors is an integer number (1786517520822).
Almost surely, 213100304444403 is an apocalyptic number.
13100304444403 is a deficient number, since it is larger than the sum of its proper divisors (1191835722173).
13100304444403 is a wasteful number, since it uses less digits than its factorization.
13100304444403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 74912885.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 13100304444403 its reverse (30444440300131), we get a palindrome (43544744744534).
The spelling of 13100304444403 in words is "thirteen trillion, one hundred billion, three hundred four million, four hundred forty-four thousand, four hundred three".
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