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13100321442301 is a prime number
BaseRepresentation
bin1011111010100010100000…
…0000011000100111111101
31201101101012220222211110121
42332220220000120213331
53204113424242123201
643510112105134541
72521316114653432
oct276505000304775
951341186884417
1013100321442301
1141a08a6a25195
121576b1b18a451
1374047cc626b2
143340b7a3bb89
1517ab81c189a1
hexbea280189fd

13100321442301 has 2 divisors, whose sum is σ = 13100321442302. Its totient is φ = 13100321442300.

The previous prime is 13100321442287. The next prime is 13100321442319. The reversal of 13100321442301 is 10324412300131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13081430314276 + 18891128025 = 3616826^2 + 137445^2 .

It is a cyclic number.

It is not a de Polignac number, because 13100321442301 - 25 = 13100321442269 is a prime.

It is a super-2 number, since 2×131003214423012 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100321442371) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550160721150 + 6550160721151.

It is an arithmetic number, because the mean of its divisors is an integer number (6550160721151).

Almost surely, 213100321442301 is an apocalyptic number.

It is an amenable number.

13100321442301 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100321442301 is an equidigital number, since it uses as much as digits as its factorization.

13100321442301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13100321442301 its reverse (10324412300131), we get a palindrome (23424733742432).

The spelling of 13100321442301 in words is "thirteen trillion, one hundred billion, three hundred twenty-one million, four hundred forty-two thousand, three hundred one".