Base | Representation |
---|---|
bin | 1011111010100010100000… |
… | …0000011000101001000011 |
3 | 1201101101012220222211120012 |
4 | 2332220220000120221003 |
5 | 3204113424242123441 |
6 | 43510112105135135 |
7 | 2521316114653562 |
oct | 276505000305103 |
9 | 51341186884505 |
10 | 13100321442371 |
11 | 41a08a6a25249 |
12 | 1576b1b18a4ab |
13 | 74047cc62737 |
14 | 3340b7a3bbd9 |
15 | 17ab81c189eb |
hex | bea28018a43 |
13100321442371 has 2 divisors, whose sum is σ = 13100321442372. Its totient is φ = 13100321442370.
The previous prime is 13100321442347. The next prime is 13100321442433. The reversal of 13100321442371 is 17324412300131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13100321442371 - 214 = 13100321425987 is a prime.
It is not a weakly prime, because it can be changed into another prime (13100321442301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550160721185 + 6550160721186.
It is an arithmetic number, because the mean of its divisors is an integer number (6550160721186).
Almost surely, 213100321442371 is an apocalyptic number.
13100321442371 is a deficient number, since it is larger than the sum of its proper divisors (1).
13100321442371 is an equidigital number, since it uses as much as digits as its factorization.
13100321442371 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 32.
The spelling of 13100321442371 in words is "thirteen trillion, one hundred billion, three hundred twenty-one million, four hundred forty-two thousand, three hundred seventy-one".
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