Base | Representation |
---|---|
bin | 111101000000001110… |
… | …0100110011110000101 |
3 | 110112010220010201212221 |
4 | 1322000130212132011 |
5 | 4121244011001013 |
6 | 140103222212341 |
7 | 12315254425306 |
oct | 1720034463605 |
9 | 415126121787 |
10 | 131004000133 |
11 | 50616385306 |
12 | 21480b840b1 |
13 | c479bb2656 |
14 | 64aa9787ad |
15 | 361b08508d |
hex | 1e80726785 |
131004000133 has 2 divisors, whose sum is σ = 131004000134. Its totient is φ = 131004000132.
The previous prime is 131004000109. The next prime is 131004000143. The reversal of 131004000133 is 331000400131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 128266408449 + 2737591684 = 358143^2 + 52322^2 .
It is a cyclic number.
It is not a de Polignac number, because 131004000133 - 225 = 130970445701 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131004000143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65502000066 + 65502000067.
It is an arithmetic number, because the mean of its divisors is an integer number (65502000067).
Almost surely, 2131004000133 is an apocalyptic number.
It is an amenable number.
131004000133 is a deficient number, since it is larger than the sum of its proper divisors (1).
131004000133 is an equidigital number, since it uses as much as digits as its factorization.
131004000133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 131004000133 its reverse (331000400131), we get a palindrome (462004400264).
The spelling of 131004000133 in words is "one hundred thirty-one billion, four million, one hundred thirty-three", and thus it is an aban number.
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