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1310040101 = 1968949479
BaseRepresentation
bin100111000010101…
…1010000000100101
310101022001221011202
41032011122000211
510140332240401
6333554412245
744315104616
oct11605320045
93338057152
101310040101
11612535577
12306891085
1317b541b76
14c5db5c0d
157a02506b
hex4e15a025

1310040101 has 4 divisors (see below), whose sum is σ = 1378989600. Its totient is φ = 1241090604.

The previous prime is 1310040097. The next prime is 1310040103. The reversal of 1310040101 is 1010400131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1310040101 - 22 = 1310040097 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1310040103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34474721 + ... + 34474758.

It is an arithmetic number, because the mean of its divisors is an integer number (344747400).

Almost surely, 21310040101 is an apocalyptic number.

It is an amenable number.

1310040101 is a deficient number, since it is larger than the sum of its proper divisors (68949499).

1310040101 is an equidigital number, since it uses as much as digits as its factorization.

1310040101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68949498.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 1310040101 is about 36194.4761116942. The cubic root of 1310040101 is about 1094.1953461045.

Adding to 1310040101 its reverse (1010400131), we get a palindrome (2320440232).

The spelling of 1310040101 in words is "one billion, three hundred ten million, forty thousand, one hundred one".

Divisors: 1 19 68949479 1310040101