Base | Representation |
---|---|
bin | 11000011001101100… |
… | …00100010101011011 |
3 | 1020210222201101010111 |
4 | 30030312010111123 |
5 | 203312200331021 |
6 | 10003535025151 |
7 | 642432402604 |
oct | 141466042533 |
9 | 36728641114 |
10 | 13100402011 |
11 | 5612920a24 |
12 | 265736b1b7 |
13 | 130a126488 |
14 | 8c3c22dab |
15 | 51a1858e1 |
hex | 30cd8455b |
13100402011 has 8 divisors (see below), whose sum is σ = 13878390960. Its totient is φ = 12323232768.
The previous prime is 13100401997. The next prime is 13100402053. The reversal of 13100402011 is 11020400131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13100402011 - 221 = 13098304859 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13100401982 and 13100402000.
It is not an unprimeable number, because it can be changed into a prime (13100402411) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 171861 + ... + 236086.
It is an arithmetic number, because the mean of its divisors is an integer number (1734798870).
Almost surely, 213100402011 is an apocalyptic number.
13100402011 is a deficient number, since it is larger than the sum of its proper divisors (777988949).
13100402011 is a wasteful number, since it uses less digits than its factorization.
13100402011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 409853.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 13100402011 its reverse (11020400131), we get a palindrome (24120802142).
The spelling of 13100402011 in words is "thirteen billion, one hundred million, four hundred two thousand, eleven".
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