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13100423411473 is a prime number
BaseRepresentation
bin1011111010100010111000…
…0101010111011100010001
31201101101111000212101212121
42332220232011113130101
53204114131343131343
643510130150454241
72521321463456566
oct276505605273421
951341430771777
1013100423411473
1141a0949541132
121576b49364381
13740498115598
143340c73c286d
1517ab8ab5baed
hexbea2e157711

13100423411473 has 2 divisors, whose sum is σ = 13100423411474. Its totient is φ = 13100423411472.

The previous prime is 13100423411431. The next prime is 13100423411479. The reversal of 13100423411473 is 37411432400131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9785591445249 + 3314831966224 = 3128193^2 + 1820668^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13100423411473 is a prime.

It is not a weakly prime, because it can be changed into another prime (13100423411479) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550211705736 + 6550211705737.

It is an arithmetic number, because the mean of its divisors is an integer number (6550211705737).

Almost surely, 213100423411473 is an apocalyptic number.

It is an amenable number.

13100423411473 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100423411473 is an equidigital number, since it uses as much as digits as its factorization.

13100423411473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24192, while the sum is 34.

The spelling of 13100423411473 in words is "thirteen trillion, one hundred billion, four hundred twenty-three million, four hundred eleven thousand, four hundred seventy-three".