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13100423411431 is a prime number
BaseRepresentation
bin1011111010100010111000…
…0101010111011011100111
31201101101111000212101211001
42332220232011113123213
53204114131343131211
643510130150454131
72521321463456506
oct276505605273347
951341430771731
1013100423411431
1141a09495410a4
121576b49364347
13740498115565
143340c73c283d
1517ab8ab5bac1
hexbea2e1576e7

13100423411431 has 2 divisors, whose sum is σ = 13100423411432. Its totient is φ = 13100423411430.

The previous prime is 13100423411429. The next prime is 13100423411473. The reversal of 13100423411431 is 13411432400131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13100423411431 - 21 = 13100423411429 is a prime.

It is a super-2 number, since 2×131004234114312 (a number of 27 digits) contains 22 as substring.

Together with 13100423411429, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 13100423411431.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13100423441431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550211705715 + 6550211705716.

It is an arithmetic number, because the mean of its divisors is an integer number (6550211705716).

Almost surely, 213100423411431 is an apocalyptic number.

13100423411431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13100423411431 is an equidigital number, since it uses as much as digits as its factorization.

13100423411431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 13100423411431 its reverse (13411432400131), we get a palindrome (26511855811562).

The spelling of 13100423411431 in words is "thirteen trillion, one hundred billion, four hundred twenty-three million, four hundred eleven thousand, four hundred thirty-one".