Base | Representation |
---|---|
bin | 10011000100000100101… |
… | …011000000111110100101 |
3 | 11122020110011210120010221 |
4 | 103010010223000332211 |
5 | 132430432103112331 |
6 | 2441454200444341 |
7 | 163435045154161 |
oct | 23040453007645 |
9 | 4566404716127 |
10 | 1310043410341 |
11 | 46564a397016 |
12 | 191a8aa796b1 |
13 | 966c8aa37b3 |
14 | 475993abca1 |
15 | 24125a0a711 |
hex | 13104ac0fa5 |
1310043410341 has 48 divisors (see below), whose sum is σ = 1406001081600. Its totient is φ = 1219742784000.
The previous prime is 1310043410323. The next prime is 1310043410399. The reversal of 1310043410341 is 1430143400131.
It is a happy number.
It is not a de Polignac number, because 1310043410341 - 211 = 1310043408293 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1310043410311) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 477942231 + ... + 477944971.
It is an arithmetic number, because the mean of its divisors is an integer number (29291689200).
Almost surely, 21310043410341 is an apocalyptic number.
It is an amenable number.
1310043410341 is a deficient number, since it is larger than the sum of its proper divisors (95957671259).
1310043410341 is an equidigital number, since it uses as much as digits as its factorization.
1310043410341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3022 (or 2981 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 1310043410341 its reverse (1430143400131), we get a palindrome (2740186810472).
The spelling of 1310043410341 in words is "one trillion, three hundred ten billion, forty-three million, four hundred ten thousand, three hundred forty-one".
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