1310043431 has 2 divisors, whose sum is σ = 1310043432. Its totient is φ = 1310043430.

The previous prime is 1310043403. The next prime is 1310043433. The reversal of 1310043431 is 1343400131.

It is a strong prime.

It is an emirp because it is prime and its reverse (1343400131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1310043431 - 2¹⁸ = 1309781287 is a prime.

It is a super-2 number, since 2×1310043431² = 3432427582212503522, which contains 22 as substring.

Together with 1310043433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310043433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655021715 + 655021716.

It is an arithmetic number, because the mean of its divisors is an integer number (655021716).

Almost surely, 2^1310043431 is an apocalyptic number.

1310043431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310043431 is an equidigital number, since it uses as much as digits as its factorization.

1310043431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 20.

The square root of 1310043431 is about 36194.5221131596. The cubic root of 1310043431 is about 1094.1962732180.

Adding to 1310043431 its reverse (1343400131), we get a palindrome (2653443562).

The spelling of 1310043431 in words is "one billion, three hundred ten million, forty-three thousand, four hundred thirty-one".