1310044031 has 2 divisors, whose sum is σ = 1310044032. Its totient is φ = 1310044030.

The previous prime is 1310044009. The next prime is 1310044039. The reversal of 1310044031 is 1304400131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1310044031 is a prime.

It is a super-2 number, since 2×1310044031² = 3432430726317457922, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310044039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655022015 + 655022016.

It is an arithmetic number, because the mean of its divisors is an integer number (655022016).

Almost surely, 2^1310044031 is an apocalyptic number.

1310044031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310044031 is an equidigital number, since it uses as much as digits as its factorization.

1310044031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1310044031 is about 36194.5304017057. The cubic root of 1310044031 is about 1094.1964402653.

Adding to 1310044031 its reverse (1304400131), we get a palindrome (2614444162).

The spelling of 1310044031 in words is "one billion, three hundred ten million, forty-four thousand, thirty-one".