1310051957545 has 4 divisors (see below), whose sum is σ = 1572062349060. Its totient is φ = 1048041566032.

The previous prime is 1310051957537. The next prime is 1310051957563. The reversal of 1310051957545 is 5457591500131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 464382279936 + 845669677609 = 681456^2 + 919603^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310051957545 - 2³ = 1310051957537 is a prime.

It is a super-2 number, since 2×1310051957545² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1310051957495 and 1310051957504.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131005195750 + ... + 131005195759.

It is an arithmetic number, because the mean of its divisors is an integer number (393015587265).

Almost surely, 2^{1310051957545} is an apocalyptic number.

It is an amenable number.

1310051957545 is a deficient number, since it is larger than the sum of its proper divisors (262010391515).

1310051957545 is an equidigital number, since it uses as much as digits as its factorization.

1310051957545 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 262010391514.

The product of its (nonzero) digits is 472500, while the sum is 46.

The spelling of 1310051957545 in words is "one trillion, three hundred ten billion, fifty-one million, nine hundred fifty-seven thousand, five hundred forty-five".