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13101004781 is a prime number
BaseRepresentation
bin11000011001110000…
…10111011111101101
31020211000211222222022
430030320113133231
5203312324123111
610003555555525
7642440463134
oct141470273755
936730758868
1013101004781
1156131a2887
1226575bbba5
13130a2a7947
148c3d3c91b
1551a2542db
hex30ce177ed

13101004781 has 2 divisors, whose sum is σ = 13101004782. Its totient is φ = 13101004780.

The previous prime is 13101004751. The next prime is 13101004793. The reversal of 13101004781 is 18740010131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8632082281 + 4468922500 = 92909^2 + 66850^2 .

It is an emirp because it is prime and its reverse (18740010131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13101004781 - 26 = 13101004717 is a prime.

It is a super-2 number, since 2×131010047812 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13101004781.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13101004751) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550502390 + 6550502391.

It is an arithmetic number, because the mean of its divisors is an integer number (6550502391).

Almost surely, 213101004781 is an apocalyptic number.

It is an amenable number.

13101004781 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101004781 is an equidigital number, since it uses as much as digits as its factorization.

13101004781 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 672, while the sum is 26.

The spelling of 13101004781 in words is "thirteen billion, one hundred one million, four thousand, seven hundred eighty-one".