Base | Representation |
---|---|
bin | 11000011001110000… |
… | …10111011111111001 |
3 | 1020211000211222222202 |
4 | 30030320113133321 |
5 | 203312324123133 |
6 | 10003555555545 |
7 | 642440463152 |
oct | 141470273771 |
9 | 36730758882 |
10 | 13101004793 |
11 | 56131a2898 |
12 | 26575bbbb5 |
13 | 130a2a7956 |
14 | 8c3d3c929 |
15 | 51a2542e8 |
hex | 30ce177f9 |
13101004793 has 2 divisors, whose sum is σ = 13101004794. Its totient is φ = 13101004792.
The previous prime is 13101004781. The next prime is 13101004859. The reversal of 13101004793 is 39740010131.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9571100224 + 3529904569 = 97832^2 + 59413^2 .
It is a cyclic number.
It is not a de Polignac number, because 13101004793 - 28 = 13101004537 is a prime.
It is not a weakly prime, because it can be changed into another prime (13101004193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550502396 + 6550502397.
It is an arithmetic number, because the mean of its divisors is an integer number (6550502397).
Almost surely, 213101004793 is an apocalyptic number.
It is an amenable number.
13101004793 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101004793 is an equidigital number, since it uses as much as digits as its factorization.
13101004793 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 29.
The spelling of 13101004793 in words is "thirteen billion, one hundred one million, four thousand, seven hundred ninety-three".
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