Base | Representation |
---|---|
bin | 11000011001110000… |
… | …10111100001001111 |
3 | 1020211000212000002221 |
4 | 30030320113201033 |
5 | 203312324124004 |
6 | 10004000000211 |
7 | 642440463334 |
oct | 141470274117 |
9 | 36730760087 |
10 | 13101004879 |
11 | 56131a2966 |
12 | 2657600067 |
13 | 130a2a79c1 |
14 | 8c3d3c98b |
15 | 51a254354 |
hex | 30ce1784f |
13101004879 has 2 divisors, whose sum is σ = 13101004880. Its totient is φ = 13101004878.
The previous prime is 13101004867. The next prime is 13101004883. The reversal of 13101004879 is 97840010131.
13101004879 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13101004879 - 27 = 13101004751 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13101004859) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550502439 + 6550502440.
It is an arithmetic number, because the mean of its divisors is an integer number (6550502440).
Almost surely, 213101004879 is an apocalyptic number.
13101004879 is a deficient number, since it is larger than the sum of its proper divisors (1).
13101004879 is an equidigital number, since it uses as much as digits as its factorization.
13101004879 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 34.
The spelling of 13101004879 in words is "thirteen billion, one hundred one million, four thousand, eight hundred seventy-nine".
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