Base | Representation |
---|---|
bin | 11101110010011100101011… |
… | …110011101100101000100101 |
3 | 122011212110000200112000211021 |
4 | 131302130223303230220211 |
5 | 114132432212313333331 |
6 | 1142345115214411141 |
7 | 36411111651360550 |
oct | 3562345363545045 |
9 | 564773020460737 |
10 | 131010122402341 |
11 | 3882009873a896 |
12 | 1283a780b00ab1 |
13 | 58142809c66c0 |
14 | 244ccd0b0b697 |
15 | 1022d197ea211 |
hex | 77272bceca25 |
131010122402341 has 32 divisors (see below), whose sum is σ = 171122415464448. Its totient is φ = 97333617807360.
The previous prime is 131010122402339. The next prime is 131010122402353. The reversal of 131010122402341 is 143204221010131.
It is a cyclic number.
It is not a de Polignac number, because 131010122402341 - 21 = 131010122402339 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131010122402381) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 97120645 + ... + 98460346.
It is an arithmetic number, because the mean of its divisors is an integer number (5347575483264).
Almost surely, 2131010122402341 is an apocalyptic number.
It is an amenable number.
131010122402341 is a deficient number, since it is larger than the sum of its proper divisors (40112293062107).
131010122402341 is a wasteful number, since it uses less digits than its factorization.
131010122402341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 195581461.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 131010122402341 its reverse (143204221010131), we get a palindrome (274214343412472).
The spelling of 131010122402341 in words is "one hundred thirty-one trillion, ten billion, one hundred twenty-two million, four hundred two thousand, three hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •