131010144114431 has 4 divisors (see below), whose sum is σ = 131010584201592. Its totient is φ = 131009704027272.

The previous prime is 131010144114347. The next prime is 131010144114467. The reversal of 131010144114431 is 134411441010131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131010144114431 is a prime.

It is a super-2 number, since 2×131010144114431² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131010144114394 and 131010144114403.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131010144104431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 219596741 + ... + 220192526.

It is an arithmetic number, because the mean of its divisors is an integer number (32752646050398).

Almost surely, 2^{131010144114431} is an apocalyptic number.

131010144114431 is a deficient number, since it is larger than the sum of its proper divisors (440087161).

131010144114431 is an equidigital number, since it uses as much as digits as its factorization.

131010144114431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 440087160.

The product of its (nonzero) digits is 2304, while the sum is 29.

Adding to 131010144114431 its reverse (134411441010131), we get a palindrome (265421585124562).

The spelling of 131010144114431 in words is "one hundred thirty-one trillion, ten billion, one hundred forty-four million, one hundred fourteen thousand, four hundred thirty-one".