Search a number
-
+
1310102023 is a prime number
BaseRepresentation
bin100111000010110…
…1001001000000111
310101022012002010011
41032011221020013
510140341231043
6334000011051
744315453266
oct11605511007
93338162104
101310102023
1161257804a
12306900a87
1317b5640c9
14c5dd05dd
157a03859d
hex4e169207

1310102023 has 2 divisors, whose sum is σ = 1310102024. Its totient is φ = 1310102022.

The previous prime is 1310102009. The next prime is 1310102029. The reversal of 1310102023 is 3202010131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1310102023 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1310101994 and 1310102012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1310102029) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655051011 + 655051012.

It is an arithmetic number, because the mean of its divisors is an integer number (655051012).

Almost surely, 21310102023 is an apocalyptic number.

1310102023 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310102023 is an equidigital number, since it uses as much as digits as its factorization.

1310102023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 13.

The square root of 1310102023 is about 36195.3315083589. The cubic root of 1310102023 is about 1094.2125857032.

Adding to 1310102023 its reverse (3202010131), we get a palindrome (4512112154).

The spelling of 1310102023 in words is "one billion, three hundred ten million, one hundred two thousand, twenty-three".