Base | Representation |
---|---|
bin | 100111000010110… |
… | …1001001010111001 |
3 | 10101022012002100202 |
4 | 1032011221022321 |
5 | 10140341232301 |
6 | 334000011545 |
7 | 44315453642 |
oct | 11605511271 |
9 | 3338162322 |
10 | 1310102201 |
11 | 6125781a1 |
12 | 306900bb5 |
13 | 17b564205 |
14 | c5dd06c9 |
15 | 7a03866b |
hex | 4e1692b9 |
1310102201 has 2 divisors, whose sum is σ = 1310102202. Its totient is φ = 1310102200.
The previous prime is 1310102197. The next prime is 1310102203. The reversal of 1310102201 is 1022010131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1302127225 + 7974976 = 36085^2 + 2824^2 .
It is a cyclic number.
It is not a de Polignac number, because 1310102201 - 22 = 1310102197 is a prime.
Together with 1310102203, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1310102203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655051100 + 655051101.
It is an arithmetic number, because the mean of its divisors is an integer number (655051101).
Almost surely, 21310102201 is an apocalyptic number.
It is an amenable number.
1310102201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1310102201 is an equidigital number, since it uses as much as digits as its factorization.
1310102201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 11.
The square root of 1310102201 is about 36195.3339672395. Note that the first 3 decimals coincide. The cubic root of 1310102201 is about 1094.2126352591.
Adding to 1310102201 its reverse (1022010131), we get a palindrome (2332112332).
The spelling of 1310102201 in words is "one billion, three hundred ten million, one hundred two thousand, two hundred one".
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