Base | Representation |
---|---|
bin | 11101110010011100111101… |
… | …000010001100000001010111 |
3 | 122011212110202211100022201122 |
4 | 131302130331002030001113 |
5 | 114132433310310213331 |
6 | 1142345204021114155 |
7 | 36411122061052133 |
oct | 3562347502140127 |
9 | 564773684308648 |
10 | 131010411413591 |
11 | 38820226899266 |
12 | 1283a84185895b |
13 | 58142c8847888 |
14 | 244cd1b2603c3 |
15 | 1022d34d8817b |
hex | 77273d08c057 |
131010411413591 has 2 divisors, whose sum is σ = 131010411413592. Its totient is φ = 131010411413590.
The previous prime is 131010411413377. The next prime is 131010411413599. The reversal of 131010411413591 is 195314114010131.
It is a strong prime.
It is an emirp because it is prime and its reverse (195314114010131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131010411413591 - 226 = 131010344304727 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131010411413599) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505205706795 + 65505205706796.
It is an arithmetic number, because the mean of its divisors is an integer number (65505205706796).
Almost surely, 2131010411413591 is an apocalyptic number.
131010411413591 is a deficient number, since it is larger than the sum of its proper divisors (1).
131010411413591 is an equidigital number, since it uses as much as digits as its factorization.
131010411413591 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6480, while the sum is 35.
The spelling of 131010411413591 in words is "one hundred thirty-one trillion, ten billion, four hundred eleven million, four hundred thirteen thousand, five hundred ninety-one".
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