131010440131231 has 4 divisors (see below), whose sum is σ = 131010545091112. Its totient is φ = 131010335171352.

The previous prime is 131010440131229. The next prime is 131010440131261. The reversal of 131010440131231 is 132131044010131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131010440131231 - 2¹ = 131010440131229 is a prime.

It is a super-2 number, since 2×131010440131231² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131010440131196 and 131010440131205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131010440131211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50584836 + ... + 53111641.

It is an arithmetic number, because the mean of its divisors is an integer number (32752636272778).

Almost surely, 2^{131010440131231} is an apocalyptic number.

131010440131231 is a deficient number, since it is larger than the sum of its proper divisors (104959881).

131010440131231 is a wasteful number, since it uses less digits than its factorization.

131010440131231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 104959880.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 131010440131231 its reverse (132131044010131), we get a palindrome (263141484141362).

The spelling of 131010440131231 in words is "one hundred thirty-one trillion, ten billion, four hundred forty million, one hundred thirty-one thousand, two hundred thirty-one".