Base | Representation |
---|---|
bin | 111101000000011011… |
… | …1011011100011010101 |
3 | 110112011101101001120122 |
4 | 1322000313123203111 |
5 | 4121302311031201 |
6 | 140104033041325 |
7 | 12315401260211 |
oct | 1720067334325 |
9 | 415141331518 |
10 | 131011033301 |
11 | 5061a349445 |
12 | 214833b6245 |
13 | c47b4a59a5 |
14 | 64ab889941 |
15 | 361b9c3e1b |
hex | 1e80ddb8d5 |
131011033301 has 2 divisors, whose sum is σ = 131011033302. Its totient is φ = 131011033300.
The previous prime is 131011033267. The next prime is 131011033403. The reversal of 131011033301 is 103330110131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 91779308401 + 39231724900 = 302951^2 + 198070^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131011033301 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131011033301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131011033801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505516650 + 65505516651.
It is an arithmetic number, because the mean of its divisors is an integer number (65505516651).
Almost surely, 2131011033301 is an apocalyptic number.
It is an amenable number.
131011033301 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011033301 is an equidigital number, since it uses as much as digits as its factorization.
131011033301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 131011033301 its reverse (103330110131), we get a palindrome (234341143432).
The spelling of 131011033301 in words is "one hundred thirty-one billion, eleven million, thirty-three thousand, three hundred one".
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