Base | Representation |
---|---|
bin | 11101110010011101100101… |
… | …111011011110000101101100 |
3 | 122011212112112122101001122111 |
4 | 131302131211323132011230 |
5 | 114132441211431042234 |
6 | 1142345400050453404 |
7 | 36411145061621623 |
oct | 3562354573360554 |
9 | 564775478331574 |
10 | 131011097518444 |
11 | 38820549107a70 |
12 | 1283a9b3594264 |
13 | 58143a7a30490 |
14 | 244cd8441c6ba |
15 | 1022d75213664 |
hex | 772765ede16c |
131011097518444 has 96 divisors (see below), whose sum is σ = 274459056286464. Its totient is φ = 53927522737920.
The previous prime is 131011097518369. The next prime is 131011097518447. The reversal of 131011097518444 is 444815790110131.
It is a super-2 number, since 2×1310110975184442 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131011097518447) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 335797267 + ... + 336187189.
It is an arithmetic number, because the mean of its divisors is an integer number (2858948502984).
Almost surely, 2131011097518444 is an apocalyptic number.
It is an amenable number.
131011097518444 is an abundant number, since it is smaller than the sum of its proper divisors (143447958768020).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131011097518444 is a wasteful number, since it uses less digits than its factorization.
131011097518444 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 401087 (or 401085 counting only the distinct ones).
The product of its (nonzero) digits is 483840, while the sum is 49.
The spelling of 131011097518444 in words is "one hundred thirty-one trillion, eleven billion, ninety-seven million, five hundred eighteen thousand, four hundred forty-four".
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