| Base | Representation |
|---|---|
| bin | 1011111010100101011100… |
| … | …0000111111101000000000 |
| 3 | 1201101110020220001101020120 |
| 4 | 2332221113000333220000 |
| 5 | 3204122033143144300 |
| 6 | 43510322241340240 |
| 7 | 2521344502500120 |
| oct | 276512700775000 |
| 9 | 51343226041216 |
| 10 | 13101110131200 |
| 11 | 41a117113a8a3 |
| 12 | 15770bb337680 |
| 13 | 740577485010 |
| 14 | 3341506a0c80 |
| 15 | 17abcb0a93a0 |
| hex | bea5703fa00 |
13101110131200 has 1920 divisors, whose sum is σ = 55275290155008. Its totient is φ = 2661533614080.
The previous prime is 13101110131199. The next prime is 13101110131201. The reversal of 13101110131200 is 213101110131.
It is an interprime number because it is at equal distance from previous prime (13101110131199) and next prime (13101110131201).
It is a tau number, because it is divible by the number of its divisors (1920).
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 13101110131200.
It is not an unprimeable number, because it can be changed into a prime (13101110131201) by changing a digit.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 13834329127 + ... + 13834330073.
Almost surely, 213101110131200 is an apocalyptic number.
13101110131200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13101110131200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (27637645077504).
13101110131200 is an abundant number, since it is smaller than the sum of its proper divisors (42174180023808).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13101110131200 is a wasteful number, since it uses less digits than its factorization.
13101110131200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1142 (or 1121 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 15.
Adding to 13101110131200 its reverse (213101110131), we get a palindrome (13314211241331).
The spelling of 13101110131200 in words is "thirteen trillion, one hundred one billion, one hundred ten million, one hundred thirty-one thousand, two hundred".
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