Base | Representation |
---|---|
bin | 11101110010011101100111… |
… | …100001010000011101010111 |
3 | 122011212112121111120200122112 |
4 | 131302131213201100131113 |
5 | 114132441240243420203 |
6 | 1142345402442421235 |
7 | 36411145534463333 |
oct | 3562354741203527 |
9 | 564775544520575 |
10 | 131011124201303 |
11 | 38820562182215 |
12 | 1283aa0050181b |
13 | 58143b0413658 |
14 | 244cd87ba67c3 |
15 | 1022d777346d8 |
hex | 772767850757 |
131011124201303 has 4 divisors (see below), whose sum is σ = 131035070674368. Its totient is φ = 130987177728240.
The previous prime is 131011124201281. The next prime is 131011124201329. The reversal of 131011124201303 is 303102421110131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131011124201303 - 28 = 131011124201047 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131011124200303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11973228326 + ... + 11973239267.
It is an arithmetic number, because the mean of its divisors is an integer number (32758767668592).
Almost surely, 2131011124201303 is an apocalyptic number.
131011124201303 is a deficient number, since it is larger than the sum of its proper divisors (23946473065).
131011124201303 is an equidigital number, since it uses as much as digits as its factorization.
131011124201303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23946473064.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 131011124201303 its reverse (303102421110131), we get a palindrome (434113545311434).
The spelling of 131011124201303 in words is "one hundred thirty-one trillion, eleven billion, one hundred twenty-four million, two hundred one thousand, three hundred three".
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