Base | Representation |
---|---|
bin | 11101110010011101100111… |
… | …110111011011001000111101 |
3 | 122011212112121220111220201201 |
4 | 131302131213313123020331 |
5 | 114132441243240342341 |
6 | 1142345403211135501 |
7 | 36411145635044644 |
oct | 3562354767331075 |
9 | 564775556456651 |
10 | 131011130012221 |
11 | 38820565491028 |
12 | 1283aa02444591 |
13 | 58143b1699574 |
14 | 244cd8887a35b |
15 | 1022d77ed1331 |
hex | 772767ddb23d |
131011130012221 has 2 divisors, whose sum is σ = 131011130012222. Its totient is φ = 131011130012220.
The previous prime is 131011130012179. The next prime is 131011130012249. The reversal of 131011130012221 is 122210031110131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 115422491432196 + 15588638580025 = 10743486^2 + 3948245^2 .
It is a cyclic number.
It is not a de Polignac number, because 131011130012221 - 27 = 131011130012093 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131011131012221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505565006110 + 65505565006111.
It is an arithmetic number, because the mean of its divisors is an integer number (65505565006111).
Almost surely, 2131011130012221 is an apocalyptic number.
It is an amenable number.
131011130012221 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011130012221 is an equidigital number, since it uses as much as digits as its factorization.
131011130012221 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 131011130012221 its reverse (122210031110131), we get a palindrome (253221161122352).
The spelling of 131011130012221 in words is "one hundred thirty-one trillion, eleven billion, one hundred thirty million, twelve thousand, two hundred twenty-one".
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