131011131211351 has 2 divisors, whose sum is σ = 131011131211352. Its totient is φ = 131011131211350.

The previous prime is 131011131211297. The next prime is 131011131211469. The reversal of 131011131211351 is 153112131110131.

It is a weak prime.

It is an emirp because it is prime and its reverse (153112131110131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131011131211351 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131011431211351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505565605675 + 65505565605676.

It is an arithmetic number, because the mean of its divisors is an integer number (65505565605676).

Almost surely, 2^{131011131211351} is an apocalyptic number.

131011131211351 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011131211351 is an equidigital number, since it uses as much as digits as its factorization.

131011131211351 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 270, while the sum is 25.

Adding to 131011131211351 its reverse (153112131110131), we get a palindrome (284123262321482).

The spelling of 131011131211351 in words is "one hundred thirty-one trillion, eleven billion, one hundred thirty-one million, two hundred eleven thousand, three hundred fifty-one".