Base | Representation |
---|---|
bin | 11101110010011101100111… |
… | …111011111111111010001011 |
3 | 122011212112121222202211200212 |
4 | 131302131213323333322023 |
5 | 114132441244042231103 |
6 | 1142345403252551335 |
7 | 36411145651201052 |
oct | 3562354773777213 |
9 | 564775558684625 |
10 | 131011131211403 |
11 | 3882056612aa93 |
12 | 1283aa0292254b |
13 | 58143b19c9341 |
14 | 244cd88aad399 |
15 | 1022d7816b7d8 |
hex | 772767effe8b |
131011131211403 has 16 divisors (see below), whose sum is σ = 138261097989120. Its totient is φ = 123796661747616.
The previous prime is 131011131211351. The next prime is 131011131211469. The reversal of 131011131211403 is 304112131110131.
It is a cyclic number.
It is not a de Polignac number, because 131011131211403 - 220 = 131011130162827 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131011131211483) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 146060576 + ... + 146954802.
It is an arithmetic number, because the mean of its divisors is an integer number (8641318624320).
Almost surely, 2131011131211403 is an apocalyptic number.
131011131211403 is a deficient number, since it is larger than the sum of its proper divisors (7249966777717).
131011131211403 is a wasteful number, since it uses less digits than its factorization.
131011131211403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 914066.
The product of its (nonzero) digits is 216, while the sum is 23.
Adding to 131011131211403 its reverse (304112131110131), we get a palindrome (435123262321534).
The spelling of 131011131211403 in words is "one hundred thirty-one trillion, eleven billion, one hundred thirty-one million, two hundred eleven thousand, four hundred three".
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