Base | Representation |
---|---|
bin | 11101110010011101100111… |
… | …111011111111111010101000 |
3 | 122011212112121222202211201221 |
4 | 131302131213323333322220 |
5 | 114132441244042231212 |
6 | 1142345403252551424 |
7 | 36411145651201123 |
oct | 3562354773777250 |
9 | 564775558684657 |
10 | 131011131211432 |
11 | 3882056613000a |
12 | 1283aa02922574 |
13 | 58143b19c9364 |
14 | 244cd88aad3ba |
15 | 1022d7816b807 |
hex | 772767effea8 |
131011131211432 has 32 divisors (see below), whose sum is σ = 245755968912000. Its totient is φ = 65476209927744.
The previous prime is 131011131211351. The next prime is 131011131211469. The reversal of 131011131211432 is 234112131110131.
It is a junction number, because it is equal to n+sod(n) for n = 131011131211397 and 131011131211406.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 288441133 + ... + 288894979.
It is an arithmetic number, because the mean of its divisors is an integer number (7679874028500).
Almost surely, 2131011131211432 is an apocalyptic number.
It is an amenable number.
131011131211432 is a deficient number, since it is larger than the sum of its proper divisors (114744837700568).
131011131211432 is a wasteful number, since it uses less digits than its factorization.
131011131211432 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 469945 (or 469941 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 25.
Adding to 131011131211432 its reverse (234112131110131), we get a palindrome (365123262321563).
The spelling of 131011131211432 in words is "one hundred thirty-one trillion, eleven billion, one hundred thirty-one million, two hundred eleven thousand, four hundred thirty-two".
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