Base | Representation |
---|---|
bin | 11101110010011101101000… |
… | …011111000110010000011100 |
3 | 122011212112122122002022011011 |
4 | 131302131220133012100130 |
5 | 114132441303421144234 |
6 | 1142345404222105004 |
7 | 36411146122332205 |
oct | 3562355037062034 |
9 | 564775578068134 |
10 | 131011140412444 |
11 | 38820570344956 |
12 | 1283aa05a1b164 |
13 | 58143b389b346 |
14 | 244cd89dc65ac |
15 | 1022d78d87b64 |
hex | 7727687c641c |
131011140412444 has 48 divisors (see below), whose sum is σ = 231012385502080. Its totient is φ = 65009542671360.
The previous prime is 131011140412421. The next prime is 131011140412469. The reversal of 131011140412444 is 444214041110131.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1268981194 + ... + 1269084430.
Almost surely, 2131011140412444 is an apocalyptic number.
It is an amenable number.
131011140412444 is a deficient number, since it is larger than the sum of its proper divisors (100001245089636).
131011140412444 is a wasteful number, since it uses less digits than its factorization.
131011140412444 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 107918 (or 107916 counting only the distinct ones).
The product of its (nonzero) digits is 6144, while the sum is 31.
Adding to 131011140412444 its reverse (444214041110131), we get a palindrome (575225181522575).
The spelling of 131011140412444 in words is "one hundred thirty-one trillion, eleven billion, one hundred forty million, four hundred twelve thousand, four hundred forty-four".
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