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131011142101423 is a prime number
BaseRepresentation
bin11101110010011101101000…
…100101100010100110101111
3122011212112122202021002222221
4131302131220211202212233
5114132441304334221143
61142345404322220211
736411146142565303
oct3562355045424657
9564775582232887
10131011142101423
1138820571298901
121283aa064b4667
1358143b404003c
14244cd8a305d03
151022d790bd2ed
hex7727689629af

131011142101423 has 2 divisors, whose sum is σ = 131011142101424. Its totient is φ = 131011142101422.

The previous prime is 131011142101421. The next prime is 131011142101447. The reversal of 131011142101423 is 324101241110131.

It is a weak prime.

It is an emirp because it is prime and its reverse (324101241110131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131011142101423 - 21 = 131011142101421 is a prime.

Together with 131011142101421, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131011142101421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505571050711 + 65505571050712.

It is an arithmetic number, because the mean of its divisors is an integer number (65505571050712).

Almost surely, 2131011142101423 is an apocalyptic number.

131011142101423 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011142101423 is an equidigital number, since it uses as much as digits as its factorization.

131011142101423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 131011142101423 its reverse (324101241110131), we get a palindrome (455112383211554).

The spelling of 131011142101423 in words is "one hundred thirty-one trillion, eleven billion, one hundred forty-two million, one hundred one thousand, four hundred twenty-three".