13101115 has 4 divisors (see below), whose sum is σ = 15721344. Its totient is φ = 10480888.

The previous prime is 13101097. The next prime is 13101119. The reversal of 13101115 is 51110131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13101115 - 2⁵ = 13101083 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13101095 and 13101104.

It is not an unprimeable number, because it can be changed into a prime (13101119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1310107 + ... + 1310116.

It is an arithmetic number, because the mean of its divisors is an integer number (3930336).

Almost surely, 2^13101115 is an apocalyptic number.

13101115 is a deficient number, since it is larger than the sum of its proper divisors (2620229).

13101115 is an equidigital number, since it uses as much as digits as its factorization.

13101115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2620228.

The product of its (nonzero) digits is 15, while the sum is 13.

The square root of 13101115 is about 3619.5462422795. The cubic root of 13101115 is about 235.7415237228.

Adding to 13101115 its reverse (51110131), we get a palindrome (64211246).

The spelling of 13101115 in words is "thirteen million, one hundred one thousand, one hundred fifteen".