Search a number
-
+
131011220311331 is a prime number
BaseRepresentation
bin11101110010011101101101…
…001111111000110100100011
3122011212112212012102120211012
4131302131231033320310203
5114132441434344430311
61142345420154411135
736411151112424443
oct3562355517706443
9564775765376735
10131011220311331
1138820601457098
121283aa28730aab
1358143c72c46a9
14244cd96864123
151022d80dbb78b
hex77276d3f8d23

131011220311331 has 2 divisors, whose sum is σ = 131011220311332. Its totient is φ = 131011220311330.

The previous prime is 131011220311277. The next prime is 131011220311459. The reversal of 131011220311331 is 133113022110131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131011220311331 is a prime.

It is a super-2 number, since 2×1310112203113312 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131011220311297 and 131011220311306.

It is not a weakly prime, because it can be changed into another prime (131011220310331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505610155665 + 65505610155666.

It is an arithmetic number, because the mean of its divisors is an integer number (65505610155666).

Almost surely, 2131011220311331 is an apocalyptic number.

131011220311331 is a deficient number, since it is larger than the sum of its proper divisors (1).

131011220311331 is an equidigital number, since it uses as much as digits as its factorization.

131011220311331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 131011220311331 its reverse (133113022110131), we get a palindrome (264124242421462).

The spelling of 131011220311331 in words is "one hundred thirty-one trillion, eleven billion, two hundred twenty million, three hundred eleven thousand, three hundred thirty-one".