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13101130201100 = 2252131011302011
BaseRepresentation
bin1011111010100101100000…
…1101100011100000001100
31201101110022021211000222012
42332221120031203200030
53204122103312413400
643510324235440352
72521345135210004
oct276513015434014
951343267730865
1013101130201100
1141a11814a8697
121577105bb60b8
1374057b6911b6
14334153207004
1517abccc20d35
hexbea5836380c

13101130201100 has 18 divisors (see below), whose sum is σ = 28429452536604. Its totient is φ = 5240452080400.

The previous prime is 13101130201099. The next prime is 13101130201141. The reversal of 13101130201100 is 110203110131.

It is a happy number.

It is a super-2 number, since 2×131011302011002 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 65505650906 + ... + 65505651105.

Almost surely, 213101130201100 is an apocalyptic number.

13101130201100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13101130201100 is an abundant number, since it is smaller than the sum of its proper divisors (15328322335504).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13101130201100 is a wasteful number, since it uses less digits than its factorization.

13101130201100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131011302025 (or 131011302018 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 13101130201100 its reverse (110203110131), we get a palindrome (13211333311231).

The spelling of 13101130201100 in words is "thirteen trillion, one hundred one billion, one hundred thirty million, two hundred one thousand, one hundred".

Divisors: 1 2 4 5 10 20 25 50 100 131011302011 262022604022 524045208044 655056510055 1310113020110 2620226040220 3275282550275 6550565100550 13101130201100