Base | Representation |
---|---|
bin | 111101000000011100… |
… | …0011111101000110101 |
3 | 110112011101220020010112 |
4 | 1322000320133220311 |
5 | 4121302343442211 |
6 | 140104043032405 |
7 | 12315403531241 |
oct | 1720070375065 |
9 | 415141806115 |
10 | 131011312181 |
11 | 5061a519a22 |
12 | 2148350b705 |
13 | c47b5728c9 |
14 | 64ab91d421 |
15 | 361ba2b88b |
hex | 1e80e1fa35 |
131011312181 has 2 divisors, whose sum is σ = 131011312182. Its totient is φ = 131011312180.
The previous prime is 131011312147. The next prime is 131011312193. The reversal of 131011312181 is 181213110131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 70293916900 + 60717395281 = 265130^2 + 246409^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131011312181 is a prime.
It is a super-2 number, since 2×1310113121812 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131011372181) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65505656090 + 65505656091.
It is an arithmetic number, because the mean of its divisors is an integer number (65505656091).
Almost surely, 2131011312181 is an apocalyptic number.
It is an amenable number.
131011312181 is a deficient number, since it is larger than the sum of its proper divisors (1).
131011312181 is an equidigital number, since it uses as much as digits as its factorization.
131011312181 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 23.
The spelling of 131011312181 in words is "one hundred thirty-one billion, eleven million, three hundred twelve thousand, one hundred eighty-one".
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