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13101133220303 is a prime number
BaseRepresentation
bin1011111010100101100001…
…1001000100100111001111
31201101110022111111102112112
42332221120121010213033
53204122110101022203
643510324424254235
72521345202653232
oct276513031044717
951343274442475
1013101133220303
1141a118317aaa7
12157710701137b
1374057c1aa4cb
14334153791419
1517abcd11a6d8
hexbea586449cf

13101133220303 has 2 divisors, whose sum is σ = 13101133220304. Its totient is φ = 13101133220302.

The previous prime is 13101133220299. The next prime is 13101133220317. The reversal of 13101133220303 is 30302233110131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13101133220303 - 22 = 13101133220299 is a prime.

It is a super-2 number, since 2×131011332203032 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13101133220393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550566610151 + 6550566610152.

It is an arithmetic number, because the mean of its divisors is an integer number (6550566610152).

Almost surely, 213101133220303 is an apocalyptic number.

13101133220303 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101133220303 is an equidigital number, since it uses as much as digits as its factorization.

13101133220303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 13101133220303 its reverse (30302233110131), we get a palindrome (43403366330434).

The spelling of 13101133220303 in words is "thirteen trillion, one hundred one billion, one hundred thirty-three million, two hundred twenty thousand, three hundred three".