131011410440023 has 4 divisors (see below), whose sum is σ = 136707558720048. Its totient is φ = 125315262160000.

The previous prime is 131011410439993. The next prime is 131011410440041. The reversal of 131011410440023 is 320044014110131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131011410440023 - 2⁵ = 131011410439991 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131011410440023.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131021410440023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2848074139978 + ... + 2848074140023.

It is an arithmetic number, because the mean of its divisors is an integer number (34176889680012).

Almost surely, 2^{131011410440023} is an apocalyptic number.

131011410440023 is a deficient number, since it is larger than the sum of its proper divisors (5696148280025).

131011410440023 is an equidigital number, since it uses as much as digits as its factorization.

131011410440023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5696148280024.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 131011410440023 its reverse (320044014110131), we get a palindrome (451055424550154).

The spelling of 131011410440023 in words is "one hundred thirty-one trillion, eleven billion, four hundred ten million, four hundred forty thousand, twenty-three".