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131011423 = 547239509
BaseRepresentation
bin1111100111100…
…01001101011111
3100010112001212221
413303301031133
5232014331143
621000010211
73150402334
oct763611537
9303461787
10131011423
1167a52904
1237a60967
13211b0c6a
141358498b
15b77d2ed
hex7cf135f

131011423 has 4 divisors (see below), whose sum is σ = 131251480. Its totient is φ = 130771368.

The previous prime is 131011399. The next prime is 131011457. The reversal of 131011423 is 324110131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131011423 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131011397 and 131011406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131011123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 119208 + ... + 120301.

It is an arithmetic number, because the mean of its divisors is an integer number (32812870).

Almost surely, 2131011423 is an apocalyptic number.

131011423 is a deficient number, since it is larger than the sum of its proper divisors (240057).

131011423 is an equidigital number, since it uses as much as digits as its factorization.

131011423 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 240056.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 131011423 is about 11446.0221474537. The cubic root of 131011423 is about 507.8900693680.

Adding to 131011423 its reverse (324110131), we get a palindrome (455121554).

The spelling of 131011423 in words is "one hundred thirty-one million, eleven thousand, four hundred twenty-three".

Divisors: 1 547 239509 131011423