13101201001111 has 4 divisors (see below), whose sum is σ = 13101225041952. Its totient is φ = 13101176960272.

The previous prime is 13101201001099. The next prime is 13101201001139. The reversal of 13101201001111 is 11110010210131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13101201001111 - 2⁵ = 13101201001079 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13101201001091 and 13101201001100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13101201001151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11183566 + ... + 12299371.

It is an arithmetic number, because the mean of its divisors is an integer number (3275306260488).

Almost surely, 2^{13101201001111} is an apocalyptic number.

13101201001111 is a deficient number, since it is larger than the sum of its proper divisors (24040841).

13101201001111 is an equidigital number, since it uses as much as digits as its factorization.

13101201001111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24040840.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 13101201001111 its reverse (11110010210131), we get a palindrome (24211211211242).

The spelling of 13101201001111 in words is "thirteen trillion, one hundred one billion, two hundred one million, one thousand, one hundred eleven".