Base | Representation |
---|---|
bin | 1011111010100101110001… |
… | …1011101000101101011111 |
3 | 1201101110111020001001121020 |
4 | 2332221130123220231133 |
5 | 3204122224424020221 |
6 | 43510335245135223 |
7 | 2521346655045423 |
oct | 276513433505537 |
9 | 51343436031536 |
10 | 13101201001311 |
11 | 41a1208465965 |
12 | 157712585a513 |
13 | 740590250007 |
14 | 33415c796b83 |
15 | 17abd4058ac6 |
hex | bea5c6e8b5f |
13101201001311 has 4 divisors (see below), whose sum is σ = 17468268001752. Its totient is φ = 8734134000872.
The previous prime is 13101201001283. The next prime is 13101201001349. The reversal of 13101201001311 is 11310010210131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13101201001311 - 213 = 13101200993119 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13101201000311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2183533500216 + ... + 2183533500221.
It is an arithmetic number, because the mean of its divisors is an integer number (4367067000438).
Almost surely, 213101201001311 is an apocalyptic number.
13101201001311 is a deficient number, since it is larger than the sum of its proper divisors (4367067000441).
13101201001311 is an equidigital number, since it uses as much as digits as its factorization.
13101201001311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4367067000440.
The product of its (nonzero) digits is 18, while the sum is 15.
Adding to 13101201001311 its reverse (11310010210131), we get a palindrome (24411211211442).
The spelling of 13101201001311 in words is "thirteen trillion, one hundred one billion, two hundred one million, one thousand, three hundred eleven".
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