13101201000311 has 2 divisors, whose sum is σ = 13101201000312. Its totient is φ = 13101201000310.

The previous prime is 13101201000263. The next prime is 13101201000313. The reversal of 13101201000311 is 11300010210131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13101201000311 is a prime.

Together with 13101201000313, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13101201000313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550600500155 + 6550600500156.

It is an arithmetic number, because the mean of its divisors is an integer number (6550600500156).

Almost surely, 2^{13101201000311} is an apocalyptic number.

13101201000311 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101201000311 is an equidigital number, since it uses as much as digits as its factorization.

13101201000311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 13101201000311 its reverse (11300010210131), we get a palindrome (24401211210442).

The spelling of 13101201000311 in words is "thirteen trillion, one hundred one billion, two hundred one million, three hundred eleven", and thus it is an aban number.