Search a number
-
+
131012020213 is a prime number
BaseRepresentation
bin111101000000011101…
…1001100011111110101
3110112011110020012100221
41322000323030133311
54121303034121323
6140104110134341
712315412540414
oct1720073143765
9415143205327
10131012020213
115061a962978
12214837b13b1
13c47b75cc69
1464aba6547b
15361bb1b55d
hex1e80ecc7f5

131012020213 has 2 divisors, whose sum is σ = 131012020214. Its totient is φ = 131012020212.

The previous prime is 131012020199. The next prime is 131012020273. The reversal of 131012020213 is 312020210131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127447572004 + 3564448209 = 356998^2 + 59703^2 .

It is a cyclic number.

It is not a de Polignac number, because 131012020213 - 225 = 130978465781 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131012020273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65506010106 + 65506010107.

It is an arithmetic number, because the mean of its divisors is an integer number (65506010107).

Almost surely, 2131012020213 is an apocalyptic number.

It is an amenable number.

131012020213 is a deficient number, since it is larger than the sum of its proper divisors (1).

131012020213 is an equidigital number, since it uses as much as digits as its factorization.

131012020213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 131012020213 its reverse (312020210131), we get a palindrome (443032230344).

The spelling of 131012020213 in words is "one hundred thirty-one billion, twelve million, twenty thousand, two hundred thirteen".