13101216146341 has 2 divisors, whose sum is σ = 13101216146342. Its totient is φ = 13101216146340.

The previous prime is 13101216146339. The next prime is 13101216146353. The reversal of 13101216146341 is 14364161210131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11570515190116 + 1530700956225 = 3401546^2 + 1237215^2 .

It is a cyclic number.

It is not a de Polignac number, because 13101216146341 - 2¹ = 13101216146339 is a prime.

It is a super-2 number, since 2×13101216146341² (a number of 27 digits) contains 22 as substring.

Together with 13101216146339, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13101216146297 and 13101216146306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13101216146311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6550608073170 + 6550608073171.

It is an arithmetic number, because the mean of its divisors is an integer number (6550608073171).

Almost surely, 2^{13101216146341} is an apocalyptic number.

It is an amenable number.

13101216146341 is a deficient number, since it is larger than the sum of its proper divisors (1).

13101216146341 is an equidigital number, since it uses as much as digits as its factorization.

13101216146341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 34.

Adding to 13101216146341 its reverse (14364161210131), we get a palindrome (27465377356472).

The spelling of 13101216146341 in words is "thirteen trillion, one hundred one billion, two hundred sixteen million, one hundred forty-six thousand, three hundred forty-one".